SOLUTION: find three consecutive integers such that the product of 5 and the sum of the first two was 7 greater than the opposite of the third.

SOLUTION: find three consecutive integers such that the product of 5 and the sum of the first two was 7 greater than the opposite of the third.

Algebra.Com

Question 784900: find three consecutive integers such that the product of 5 and the sum of the first two was 7 greater than the opposite of the third.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

5((x-1) + x) = 7 - (x + 1)
5(2x - 1) = 7 - x - 1
10x - 5 = -x + 6
11x = 11
x = 1

The integers are 0, 1, and 2.
RELATED QUESTIONS
Find 3 consecutive integers such that the product of 5 and the sum of the first two was 7 (answered by CubeyThePenguin)

Find four consecutive odd integers such that the opposite of the sum of the first two is... (answered by CubeyThePenguin)

Find three consecutive integers such that -7 times the sum of the first and third is 12... (answered by mananth)

Find three consecutive odd integers such that the product of -7and the sum of the first... (answered by Edwin McCravy)

Find three consecutive odd integers such that -3 times the sum of the first and third is... (answered by Theo,josgarithmetic)

Please help! Find four consecutive integers such that 5 times the opposite of the first... (answered by josgarithmetic,MathTherapy)

find three consecutive integers such that the product of -5 and the sum of the first two... (answered by ewatrrr)

Find three Consecutive Integers Such That The Sum Of the first two is greater than 27 and (answered by mathie123)

find three consecutive odd integers such that three times the sum of the first two... (answered by ankor@dixie-net.com)