SOLUTION: find two consecutive integers whose product exceeds their sum by 41
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Question 780907: find two consecutive integers whose product exceeds their sum by 41
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: x, (x+1)
x(x+1) = x + (x+1) + 41
x^2 + x = 2x + 42
x^2 - x - 42 = 0
(x - 7)(x + 6) = 0
x = 7, x = -6
The integers could be -6 and -5 or 7 and 8.
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