SOLUTION: The product of 2 consecutive even integers is five thousand, one hundred two more than nine times their sum. What are the two integers?

Question 771358: The product of 2 consecutive even integers is five thousand, one hundred two more than nine times their sum. What are the two integers?
Found 2 solutions by oscargut, Alan3354:
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!

Let n and n+4 those consecutive even numbers
n(n+4) = 5102+9(n+n+4)
n^2+4n = 18n+5138
n^2-14n -5138 = 0
This equation has no integer solutions , can you check the info please ?
I can help you with all of your questions at: mthman@gmail.com
Thanks

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!

n(n+2) = 5102 + 9*(n+n+2)
n^2+2n = 18n+5120
n^2-16n -5120 = 0
(n - 80)*(n + 64) = 0
--> 80 & 82
--> -64 & -62
RELATED QUESTIONS
The product of two consecutive even integers is ten more than five times their sum. What... (answered by Fombitz)
The product of two consecutive odd integers is eight thousand, eight hundred thirty-five. (answered by nerdybill)
The product of two consecutive even integers is 76 more than 2 times their sum. Find... (answered by user_dude2008)
The product of two consecutive even integers is 10 less than five times their sum. Find... (answered by stanbon)
the product of two consecutive integers is 6 more than three times their sum. what are... (answered by Tatiana_Stebko)
The product of two consecutive even integers is 6 more than three times their sum .find... (answered by stanbon)
The product of two consecutive odd integers is seven thousand, fifty-five. What are the... (answered by ewatrrr)
If the product of two consecutive even integers is 34 larger than their sum then what... (answered by stanbon)
If the product of two consecutive even integers is 34 larger than their sum then what are (answered by ankor@dixie-net.com)