SOLUTION: Five times the first 3 consecutive even integer is 4 less than the twice of the sum of 2nd and 3rd . find the three even numbers .

Question 762767: Five times the first 3 consecutive even integer is 4 less than the twice of the sum of 2nd and 3rd . find the three even numbers .
Answer by sachi(548) (Show Source): You can put this solution on YOUR website!
let the three consecutive even integer are x-2,x,x+2
Five times the first 3 consecutive even integer is 4 less than the twice of the sum of 2nd and 3rd .
so 5[x-2]=2[x+x+2]-4
or 5x-10=4x+4-4
or x=10
so the three even numbers are 8,10,12
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