SOLUTION: find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46

Question 760719: find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46
Answer by ramkikk66(644) (Show Source): You can put this solution on YOUR website!
Let the smaller even integer be n.
Then the next consecutive even integer is n+2 (because successive even numbers have a difference of 2)
Given that smaller + 3 times the bigger number gives sum of 46. We can write it algebraically as:
---- equation (1)
Expanding the brackets, we get

Adding like terms

Subtracting 6 from both sides to get rid of the "6" on the left side

Dividing both sides by 4

So the smaller number is 10 and the next number is 12. The two consecutive even integers are 10 and 12.
To check the answer, substitute n with 10 in equation (1)
---> which is true.

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