SOLUTION: Find 3 consecutive integers such that 5 times the 2nd equals twice the sum of the 1st and 3rd.
Algebra.Com
Question 748571: Find 3 consecutive integers such that 5 times the 2nd equals twice the sum of the 1st and 3rd.
Answer by timvanswearingen(106) (Show Source): You can put this solution on YOUR website!
Let the smallest integer be x, then the middle is x+1 and the largest is x+2.
5 times the 2nd equals twice the sum of the 1st and 3rd:
The other numbers are x+1 and x+2, so they are 0 and 1.
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