SOLUTION:
Nine times a certain integer is 18 less than the square of the integer. Find the integer.
Algebra.Com
Question 748253:
Nine times a certain integer is 18 less than the square of the integer. Find the integer.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
9X=X^2+18
X^2-9X+18=0
(X-6)(X-3)=0
X-6=0
X=6 ANS.
X-3=0
X=3 ANS.
PROOFS:
9*6=6^2+18
54=36+18
54=54
9*3=3^2+18
27=9+18
27=27
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