SOLUTION: Find three consecutive even integers such that twice the sum of the second and third is 4 less than 6 times the second

Question 746898: Find three consecutive even integers such that twice the sum of the second and third is 4 less than 6 times the second
Answer by savvyhush23(50) (Show Source): You can put this solution on YOUR website!
Find three consecutive even integers such that twice the sum of the second and third is 4 less than 6 times the second
.
.
Let,
x - the first integer
x+2 - the second
x+4 - the third
.
.
twice the sum of the second and third: 2[(x + 2) + ( x + 4)]
is 4 less than 6 times the second: 2[(x + 2) + ( x + 4)] = 6(x + 2) - 4
it becomes, 4x + 12 = 6x + 8
simplifying yields, x = 2
Therefore, the three consecutive even integers are, 2, 4, and 6
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