SOLUTION: a circle of radius 5 with center at (2,7) has equation (x-2)squared+(y-7)squared=25. at which points does the line y=3 intersect with the circle

Question 746874: a circle of radius 5 with center at (2,7) has equation (x-2)squared+(y-7)squared=25. at which points does the line y=3 intersect with the circle
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
a circle of radius 5 with center at (2,7) has equation (x-2)squared+(y-7)squared=25. at which points does the line y=3 intersect with the circle
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Sub 3 for y

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x - 2 = 3
x = 5 --> (5,3)
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x - 2 = -3
x = -1 --> (-1,3)

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