SOLUTION: Find 2 consecutive odd intergers such that three times the first is eight more than the second integer. How do I set up and solve this equation?

Question 742414: Find 2 consecutive odd intergers such that three times the first is eight more than the second integer. How do I set up and solve this equation?
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
We are given
Find 2 consecutive odd integers such that three times the first is eight more than the second integer.
let i be our first odd integer, then i+2 is the second odd integer
we now have
3i = (i+2)+8
3i = i+10
2i =10
i = 5
and the solution to the problem is 5 and 7

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