SOLUTION: The product of two consecutive even integers is 10 less than five times their sum. Find two integers.

Question 736686: The product of two consecutive even integers is 10 less than five times their sum. Find two integers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The product of two consecutive even integers is 10 less than five times their sum. Find two integers.
---------------
1st: 2x
2nd: 2x+2
-----------
Equation:
2x(2x+2) = 5(2x+2x+2) - 10
-------
4x^2+4x = 20x + 10-10
---
4x^2 - 16x
---
4x(x-4) = 0
x = 0 or x = 4
---------------------
If x = 0:
2x = 0
2x+2 = 2
------
If x = 4:
2x = 8
2x+2 = 10
--------------------
Cheers,
Stan H.
====================
RELATED QUESTIONS
The product of two consecutive even integers is 76 less than 10 times their sum. Find the (answered by CubeyThePenguin)

The product of two consecutive even integers is 30 less than 15 times their sum. Find the (answered by ankor@dixie-net.com)

The product of two consecutive even integers is 18 less than 9 times their sum. Find the... (answered by dfrazzetto)

the sum of two consecutive even integers is 34 less than their product. find the... (answered by ewatrrr)

The product of two consecutive integers is 13 less than five times their sum. Find the... (answered by Boreal)

The product of two consecutive even integers is 12 less than 6 times their... (answered by mananth)

The product of two consecutive even integers is 12 less than 6 times their... (answered by TimothyLamb)

The product of two consecutive even integers is 46 less than 9 times their... (answered by CubeyThePenguin)

Product of two consecutive integers is 6 less than 6 times their sum. Find the... (answered by RAY100)