SOLUTION: The sum of the square of two consecutive odd integers is 2 more than 6 times their sum. Find the numbers.... Please!
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Question 730940: The sum of the square of two consecutive odd integers is 2 more than 6 times their sum. Find the numbers.... Please!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The sum of the square of two consecutive odd integers is 2 more than 6 times their sum. Find the numbers....
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1st: 2x-1
2nd: 2x+1
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Equation:
(2x-1)^2 + (2x+1)^2 = 6[2x-1+2x+1]+2
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4x^2 -4x + 1 + 4x^2 + 4x + 1 = 24x+2
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8x^2 = 24x
8x^2-24x = 0
8x(x-3) = 0
x = 0 or x = 3
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Cheers,
Stan H.
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