SOLUTION: find three consecutive integers such that the product of the first two is 48

SOLUTION: find three consecutive integers such that the product of the first two is 48

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Question 716055: find three consecutive integers such that the product of the first two is 48

Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

(x-1)(x) = 48
x^2 - x - 48 = 0

The solutions are not integers.
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