SOLUTION: The product of two consecutive integers is less than the square of the smaller integer. Find the larger of the two integers. The larger of the two integers is

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Question 715444: The product of two consecutive integers is less than the square of the smaller integer. Find the larger of the two integers.
The larger of the two integers is

Answer by fcabanski(1391)   (Show Source): You can put this solution on YOUR website!
Call the two consecutive integers x and x+1. Their product x*(x+1) or is less than the square of the smaller. The smaller is x, its square is and


Subtract from both sides. x<0. Then the larger of the two integers x+1 < 1.


The problem has many solutions. For example if x=-1 then x+1 = 0 and the product 0*1 = 0 is less than the smaller squared = -1 squared = 1. 0 < 1.


If x=-10, then x+1 = -9. Product: 90. Smaller squared = = 100.


Let's try an x outside the solution, and as a result an x+1 outside the solution.


If x=0 then x+1 = 1. 0*1=0 and 0 squared = 0. The product is not less than the smaller number squared. That's what we expect since x+1 < 1 is the solution.

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