SOLUTION: SOLVE: GIVEN A NUMBER SUCH THAT ONE IS 6 MORE THAN THE OTHER. FOUR TIMES LARGER ADDED TO 5 TIMES SMALLER IS 141. FIND THE NUMBERS.

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Question 715131: SOLVE: GIVEN A NUMBER SUCH THAT ONE IS 6 MORE THAN THE OTHER. FOUR TIMES LARGER ADDED TO 5 TIMES SMALLER IS 141. FIND THE NUMBERS.
Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
x = y + 6
4x + 5y = 141

Substitute the first equation into the second equation.

4(y + 6) + 5y = 141
4y + 24 + 5y = 141
9y = 117
y = 13

solution: (x, y) = (19, 13)

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