SOLUTION: Find three consecutive integers such that the sum of the least integer and the middle integer is 46 more than the greatest integer.

SOLUTION: Find three consecutive integers such that the sum of the least integer and the middle integer is 46 more than the greatest integer.

Algebra.Com

Question 714892:
Find three consecutive integers such that the sum of the least integer and the middle integer is 46 more than the greatest integer.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
LET X, X+1 & X+2 BE THE 3 INTEGERS
X+(X+1)=(X+2)+46
2X+1=X+2+46
2X-X=2+46-1
X=47 ANS.
PROOF:
47+48=49+46
95=95

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