SOLUTION: twice the smallest of three consecutive odd integers is seven more than the largest.
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Question 705911: twice the smallest of three consecutive odd integers is seven more than the largest.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
twice the smallest of three consecutive odd integers is seven more than the largest.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2(2x-1) = 2x+3+7
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4x-2 = 2x+10
2x = 12
x = 6
----
1st: 2x-1 = 11
2nd: 2x+1 = 13
3rd: 2x+3 = 15
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Cheers,
Stan H.
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