SOLUTION: Find 3 consecutive integers so that 3 times the first increased by twice the
second is 2 less than 4 times the third one.
My idea starts: 3x + 2x = 4x - 2
Algebra.Com
Question 704087: Find 3 consecutive integers so that 3 times the first increased by twice the
second is 2 less than 4 times the third one.
My idea starts: 3x + 2x = 4x - 2
Answer by sachi(548) (Show Source): You can put this solution on YOUR website!
let the 3 consecutive integers are x-1 ,x & x+1
now 3 times the first increased by twice the second is 2 less than 4 times the third one
so 3(x-1)+2x=4(x+1)-2
or 3x-3+2x=4x+4-2
or x=5
so the 3 consecutive integers are 4,5,6
ans
RELATED QUESTIONS
find three consecutive positive integers such that the square of the first increased by... (answered by TimothyLamb)
1) find 4 consecutive even integers such that the sum of twice the first, five times the... (answered by ankor@dixie-net.com)
Find three consecutive integers such that the square of the first increased by twice the... (answered by mananth)
1.one number is 11 more than another number. find the two numbers if three times the... (answered by MathLover1)
find 3 consecutive even integers such that 4 times the sum of the first and second minus... (answered by CubeyThePenguin)
find 3 consecutive even integers such that 4 times the first decreased by the second is... (answered by TimothyLamb)
Find 3 consecutive positive even integers such that 4 times the first decreased by the... (answered by LinnW)
1) find three positive consecutive odd integers such that the largest decreased by twice... (answered by stanbon)
Find 3 consecutive odd integers such that twice the first plus 3 times the third is 19... (answered by josgarithmetic,MathTherapy)