SOLUTION: Find four consecutive integers such that the sum of the two largest subtracted from twice the sum of the two smallest is 15.

Question 703801: Find four consecutive integers such that the sum of the two largest subtracted from twice the sum of the two smallest is 15.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Four consecutive integers: n, n+1, n+2, n+3.

Find four consecutive integers such that

the sum of the two largest (n+2+n+3), subtracted from (-(n+2+n+3)), twice the sum of the two smallest (2*(n+n+1)), is 15.

Solve for n, find the other three integers.
.
.
Answer: 9, 10, 11, 12
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