SOLUTION: Find three consecutive even integers such that twice the sum of the first and third integers is twenty-one more than the second integer

Question 700129: Find three consecutive even integers such that twice the sum of the first and third integers is twenty-one more than the second integer
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the consecutive even integers =
, , and
given:

This didn't work because I', going to get
5,7, and 9 which are odd numbers.
I need to call the smallest number
to make sure it will be even
My number are , ,
given:

This didn't work either.
--------------------
Now that I think about it, the problem has no solution.
It is saying that twice the sum of 2 numbers ( which is even ) is
equal to 21 plus an even number ( which is odd ), and
even cannot equal odd.
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