SOLUTION: Find three consecutive even integers such that twice the smallest number is twelve more than the largest number?

SOLUTION: Find three consecutive even integers such that twice the smallest number is twelve more than the largest number?

Algebra.Com

Question 693152: Find three consecutive even integers such that twice the smallest number is twelve more than the largest number?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

2(x-2) = 12 + (x+2)
2x - 4 = x + 14
x = 18

integers: 16, 18, 20
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