SOLUTION: Find two consecutive positive integers such that the square of the smaller increased by 4 times the larger is 64.

SOLUTION: Find two consecutive positive integers such that the square of the smaller increased by 4 times the larger is 64.

Algebra.Com

Question 692929:

Find two consecutive positive integers such that the square of the smaller increased by 4 times the larger is 64.

Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
LET X & (X+1) BE THE 2 INTEGERS.
X^2+4(X+1)=64
X^2+4X+4-64=0
X^2+4X-60=0
(X-6)(X+10)=0
X-6=0
X=6 ANS.FOR THE SMALLER INTEGER.
6+1=7 ANS. FOR THE LARGER INTEGER.
PROOF:
6^2+4*7=64
36+28=64
64=64
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