SOLUTION: Find two consecutive whole numbers such that 4/6 of the first number is 12 more than 1/3 the second number.

Algebra.Com
Question 690531: Find two consecutive whole numbers such that 4/6 of the first number is 12 more than 1/3 the second number.
Answer by Stitch(470)   (Show Source): You can put this solution on YOUR website!
Let A = X
Let B = X + 1
------------

Lets eliminate the fractions by multiplying everything by 6

Simplify

Subtract 2X from both sides

Add 72 to both sides

Divide both sides by 2


B = X + 1

RELATED QUESTIONS

Find two consecutive whole numbers such that 3/4 of the first number is 5 more than 1/2... (answered by edjones)
Find two consecutive numbers such that 3/4 of the first number is 5 more than 1/2 the... (answered by ankor@dixie-net.com)
find two consecutive whole numbers, where 3/4 of the first number is 5 more then 1/2 the (answered by mananth)
Find 2 consecutive whole numbers such that 1/4 of the first number is one more than 1/5... (answered by edjones)
Find 3 consecutive even numbers such that the sum of twice the first number and the third (answered by swincher4391)
#1 Find two consecutive odd integers such that 5 times the first integer is 12 more than (answered by ankor@dixie-net.com)
can you guys help me again.... 2. Five times the first of two consecutive integers... (answered by greenestamps,josgarithmetic)
I need to find two consecutive whole numbers such that 1/4th of the first number is one... (answered by mananth)
Find three consecutive whole numbers such that twice the sum of the two smallest numbers... (answered by tazoftroy)