SOLUTION: How do i solve two consecutive odd integers such that their product is 15 more than three times their sum?

Question 685860: How do i solve two consecutive odd integers such that their product is 15 more than three times their sum?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do i solve two consecutive odd integers such that their product is 15 more than three times their sum?
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1st: 2x-1
2nd: 2x+1
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Equation:
(2x-1)(2x+1) = 3[4x] + 15
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4x^2 -1 = 12x + 15
4x^2 - 12x -16 = 0
x^2 - 3x - 4 = 0
(x-4)(x+1) = 0
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x = 4 or x = -1
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If x = 4:
1st: 2x-1 = 7
2nd: 2x+1 = 9
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If x = -1
1st: 2x-1 = -3
2nd: 2x+1 = -1
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Cheers,
Stan H.
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