SOLUTION: find 4 consecutive integers such that twice the sum of the two largest integers is 91 more that 3 times the first integer

Question 661440: find 4 consecutive integers such that twice the sum of the two largest integers is 91 more that 3 times the first integer
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find 4 consecutive integers such that twice the sum of the two largest integers is 91 more that 3 times the first integer
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1st: x-2
2nd: x-1
3rd: x
4th: x+1
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Equation:
2(x+x+1) = 3(x-2)+91
2(2x+1) = 3x+85
4x + 2 = 3x + 85
x = 83
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1st: 81
2nd: 82
3rd: 83
4th: 84
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Cheers,
Stan H.
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