SOLUTION: find four consecutive odd numbers whose sum is 432

Question 659725: find four consecutive odd numbers whose sum is 432

Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!
Call the first integer x. Each consecutive odd integer is two more than the last, so the four are x, x+2, x+4, x+6. Their sum is 432.

x+x+2+x+4+x+6 = 432

4x+12 = 432

4x = 420

x = 105

The integers are 105, 107, 109, 111

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