SOLUTION: find two consecutive integers such that twice the first is 26 more than the second

SOLUTION: find two consecutive integers such that twice the first is 26 more than the second

Algebra.Com

Question 657048: find two consecutive integers such that twice the first is 26 more than the second

Answer by kevwill(135) (Show Source): You can put this solution on YOUR website!
Let x be the first of the two consecutive integers. Then the second is x+1. If twice the first is 26 more than the second, we have:
2x = (x+1) + 26
2x = x + 27
x = 27
The two numbers are 27 and 28.

RELATED QUESTIONS
find two consecutive intergers such that twice the first is 26 more than the... (answered by stanbon)

Find two consecutive odd integers such that twice the first is three more than the... (answered by stanbon)

Find two consecutive odd integers such that 3 times the first integer is 5 more than... (answered by vleith)

find two consecutive even integers such that seven more than twice the second is equal to (answered by Fombitz)

Find two consecutive odd integers such that 3 times first integer is 5 more than twice... (answered by macston)

find three consecutive integers such that two times the second is three more than the... (answered by CubeyThePenguin)

find two consecutive even integers such that twice the first plus twice the second is... (answered by stanbon)

Find two consecutive odd integers such that 3 times the first is 5 more than twice the... (answered by drj)

Find two consecutive integers such that twice the first is equal to the... (answered by ikleyn)