SOLUTION: the sum of two positive integers is 4 times the smaller. the positive difference of their squares is 8 times the larger. what is the product of the two integers

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Question 655490: the sum of two positive integers is 4 times the smaller. the positive difference of their squares is 8 times the larger. what is the product of the two integers
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
the sum of two integers and is 4 times the smaller.
Question states***
x + y = 4x Or
Question also states***
the positive difference of their squares is 8 times the larger
y^2 - x^2 = 8y
(3x)^2 - x^2 = 8(3x)
9x^2 - x^2 = 24x
8x^2 - 24x = 0
8x(x - 3) = 0
8x = 0 , x = 0 Toss out this solution (0 is not a positive integer)
0r
(x - 3) = 0 , x = 3 and y = 9
and...
Product of the two integers is 27

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