SOLUTION: Find two consecutive integers such that half the smaller plus three times the larger is -32

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Question 649291: Find two consecutive integers such that half the smaller plus three times the larger is -32
Answer by stanbon(57203) About Me  (Show Source):
You can put this solution on YOUR website!
Find two consecutive integers such that half the smaller plus three times the larger is -32
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1st: x
2nd: x+1
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Equations:
(1/2)x + 3(x+1) = -32
--------
Multiply thru by 2 to get:
x + 6(x+1) = -64
7x + 6 = -64
7x = -70
x = -10
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1st: -10
2nd: -9
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Cheers,
Stan H.