SOLUTION: Any help would be appreciated... Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.

Question 64770: Any help would be appreciated...
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
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Consecutive even integers: 2x, 2x+2,2x+4
EQUATION:
(2x+4)^2=(2x+2)^2+76
4x^2+16x+16 = 4x^2+8x+4+76
8x=64
x=8
1st number: 2x=16
2nd: 18
3rd: 20
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Cheers,
Stan H.
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