SOLUTION: Given three consecutive odd numbers such that the square of the second number is 192 less than the square of the third. Find those numbers.

Question 634306: Given three consecutive odd numbers such that the square of the second number is 192 less than the square of the third. Find those numbers.
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the odd numbers be n, n+2, n+4
(n+2)^2=(n+4)^2-192
n^2+4n+4=n^2+8n+16-192
4n-8n=16-192-4
-4n= 180
/4
n=45
45,47 & 49
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
consecutive ODD numbers
2n-1, 2n+1, 2n+3

The odd numbers are 45, 47, 49
RELATED QUESTIONS
Given three consecutive odd numbers such that the square of the second number is 192 less (answered by graphmatics,MathTherapy)
Given three consecutive odd numbers such that the square of the second number is 80 less... (answered by stanbon)
Given three consecutive odd numbers such that the square of the second number is 216 less (answered by Alan3354)
Given three consecutive odd numbers such that the square of the second number is 104 less (answered by stanbon,bosco20106)
Find three consecutive odd numbers such that the square of the second number is 192 less... (answered by stanbon,ankor@dixie-net.com)
Three consecutive odd integers are such that the square of the second is 96 less than the (answered by ccs2011)
There consecutive odd numbers are such that the square of the first is 72 less than the... (answered by josmiceli)
Find three consecutive odd integers such that the square of the second added to the first (answered by checkley77)
Find the biggest of three consecutive odd numbers such that the product of the second and (answered by htmentor)