SOLUTION: Find two consecutive even integers such that the smaller added to five times the larger gives a sum of 46.

SOLUTION: Find two consecutive even integers such that the smaller added to five times the larger gives a sum of 46.

Algebra.Com

Question 628194: Find two consecutive even integers such that the smaller added to five times the larger gives a sum of 46.
Answer by bondc(3) (Show Source): You can put this solution on YOUR website!
First consecutive integer: n
Second consecutive integer: n + 2 (next even integer)
n + 5(n + 2) = 46
n + 5n + 10 = 46
6n + 10 = 46
6n = 36
n = 6
n + 2 = 8
Your answer is 6 and 8.
RELATED QUESTIONS
find two consecutive even integers such that the smaller added to three times the larger... (answered by checkley71,edjones)

find two consecutive even integers such that the smaller added to five times the larger... (answered by ewatrrr)

find two consecutive even integers such that the smaller added to five times the larger... (answered by Alan3354)

Find two consecutive even integers such that the smaller added to five times the larger... (answered by CubeyThePenguin)

Find two consecutive even integers such that the smaller added to five times the larger... (answered by Cromlix)

Find two consecutive even integers such that the smaller added to two times the larger... (answered by Fombitz)

find two consecutive even integers such that the smaller added to two times the larger... (answered by xdragonfight)

Find two consecutive even integers such that the smaller added to three times the larger (answered by KMST)

Find two consecutive even integers such that the smaller added to four times the larger... (answered by MathLover1)