# SOLUTION: Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.

Algebra ->  Algebra  -> Problems-with-consecutive-odd-even-integers -> SOLUTION: Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.       Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Problems with consecutive odd even integers Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Problems-with-consecutive-odd-even-integers Question 622992: Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second. Answer by MathTherapy(1484)   (Show Source): You can put this solution on YOUR website!Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second. Let the multiplicative factor of each multiple be f Then 1st, 2nd, and 3rd multiples are: 7f, 7f + 7, and 7f + 14 7f + 7f + 14 = 3(7f + 7) – 28 14f + 14 = 21f + 21 – 28 14f – 21f = - 7 – 14 – 7f = - 21 F, or multiplicative factor = , or 3 This means that the 3 consecutive multiples are: -- 7(3) -- 7(3) + 7 -- 7(3) + 14 Send comments and “thank-yous” to “D” at MathMadEzy@aol.com