SOLUTION: Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.

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Question 622992: Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.
Answer by MathTherapy(1484) About Me  (Show Source):
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Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.

Let the multiplicative factor of each multiple be f
Then 1st, 2nd, and 3rd multiples are: 7f, 7f + 7, and 7f + 14

7f + 7f + 14 = 3(7f + 7) – 28
14f + 14 = 21f + 21 – 28
14f – 21f = - 7 – 14
– 7f = - 21

F, or multiplicative factor = -+21%2F-+7, or 3

This means that the 3 consecutive multiples are:
highlight_green%2821%29 -- 7(3)
highlight_green%2828%29 -- 7(3) + 7
highlight_green%2835%29 -- 7(3) + 14

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