SOLUTION: Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.

Question 622992: Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
Find three consecutive multiples of seven such that the sum of the first and thrid is twenty-eight less than three times the second.

Let the multiplicative factor of each multiple be f
Then 1st, 2nd, and 3rd multiples are: 7f, 7f + 7, and 7f + 14

7f + 7f + 14 = 3(7f + 7) � 28
14f + 14 = 21f + 21 � 28
14f � 21f = - 7 � 14
� 7f = - 21

F, or multiplicative factor = , or 3

This means that the 3 consecutive multiples are:
-- 7(3)
-- 7(3) + 7
-- 7(3) + 14

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