Hi,
Find three consecutive integers
,
,
in which four times the sum of the first two is the same as six times the third
4[ x + (x+1)] = 6(x+2)***
4(2x+1) = 6(x+2)
8x + 4 = 6x + 12
2x = 8
x = 4 Integers are 4,5,6
CHECKING our Answer***
4(9) = 6(6) = 36