Hi,

Find three consecutive integers, ,           

in which four times the sum of the first two is the same as six times the third

   4[ x + (x+1)] = 6(x+2)***

     4(2x+1) = 6(x+2)

     8x + 4 = 6x + 12

           2x = 8

            x = 4  Integers are 4,5,6

 CHECKING our Answer***

      4(9) = 6(6) = 36 

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