SOLUTION: One positive integer is 5 less than twice another. The sum of their squares is 325. Find the integers.
Algebra.Com
Question 601022: One positive integer is 5 less than twice another. The sum of their squares is 325. Find the integers.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent one of the integers. The other is then 
^2\ =\ 325)
Put the quadratic into standard form and solve for , then calculate . Be sure to verify whether or not either or both roots satisfy the conditions of the problem.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
one positive integer is 1 less than twice another. the sum of their squares is 218. find... (answered by Fombitz)
One positive integer is
3 less than twice another. The sum of their squares is
698. (answered by Alan3354)
One positive integer is 2 less than twice another. The sum of their squares is 1009.... (answered by Alan3354)
One positive integer is 1 less than twice another. The sum of their squares is 34. Find... (answered by Boreal)
One positive integer is 2 less than twice another. The sum of their squares is 337. Find... (answered by josgarithmetic)
One positive integer is 6 less than twice another. The sum of their squares is 296. Find... (answered by ikleyn)
One positive integer is 5 more than twice another. The sum of their squares is 185 .... (answered by CubeyThePenguin)
one positive integer is 2 less than twice another. the sum of their squares is 193. what... (answered by solver91311)
one positive integer is 1 less then twice another. the sum of their squares is 673. find... (answered by Math_prodigy)
