SOLUTION: 3 times an integer is 41 less than 5 times the next consecutive integer. Find the two consecutive integers.

SOLUTION: 3 times an integer is 41 less than 5 times the next consecutive integer. Find the two consecutive integers.

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Question 592521: 3 times an integer is 41 less than 5 times the next consecutive integer. Find the two consecutive integers.
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
3x+41=5(x+1)
3x+41=5x+5
-2x=-36
x=-36/-2
x=18
x+1=19
----------------
3(18)+41=5(18+5)
54+41=90+5
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