SOLUTION: Find two consecutive integers such that the greater of the two is 20 more than twice the smaller.

Question 587396: Find two consecutive integers such that the greater of the two is 20 more than twice the smaller.
Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!
Call the consecutive integers n and n+1.

Keep in mind the definition of integers - ...-3, -2, -1, 0, 1, 2, 3...

Plug those values into the given relationship.

The greater (n+1) is (means =) 20 more than twice the smaller (2n+20).

n+1=2n+20 | subtract n from both sides and subtract 20 from both sides
-19=n, meaning n+1 = -18.

-18 is 20 more than 2 times -19. 2*-19 = -38+20 = -18.

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