SOLUTION: The product of two consecutive negative odd integers is 899. What is the value of the two integers?

Question 587366: The product of two consecutive negative odd integers is 899. What is the value of the two integers?
Found 2 solutions by dfrazzetto, Alan3354:
Answer by dfrazzetto(283) (Show Source): You can put this solution on YOUR website!
odd integers:
2n+1, 2n+3
(2n+1)(2n+3) = 899
4n^2 + 8n + 3 = 899
4n^2 + 8n + 3 - 899 = 0
4n^2 + 8n - 896 = 0
n^2 + 2n - 224 = 0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=900 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 14, -16. Here's your graph:

plugging either of the roots in for n gives
29 and 31
29 x 31 = 899
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The product of two consecutive negative odd integers is 899. What is the value of the two integers?
------------
= almost 30, the center
--> 29 & 31

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