SOLUTION: Find three consecutive odd integers such that the sum of the smallest and 4 times the largest is 61.

Question 56851: Find three consecutive odd integers such that the sum of the smallest and 4 times the largest is 61.
Answer by Scriptor(36) (Show Source): You can put this solution on YOUR website!
Call your first odd number 2n+1 , the second one 2n+3 and the last one 2n+5
Since the sum of the smallest and 4 times the largest is 61, we get that:
(2n+1) + 4(2n+5) = 61
2n + 1 + 8n + 20 = 61
10n = 40
n =4 => 2n+1 = 9
Answer: 9,11,13
Note: we could have solved it with x instead of 2n+1, but I wanted to show clear that it is an odd number.

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