SOLUTION: Find two consecutive even integers such that the sum of the larger and twice the smaller is 62.

Question 56840: Find two consecutive even integers such that the sum of the larger and twice the smaller is 62.
Answer by mszlmb(115) (Show Source): You can put this solution on YOUR website!
Find two consecutive even integers such that the sum of the larger and twice the smaller is 62.
x is smaller y is larger:
They are consecutive AND EVEN, so x+2=y
Large+2Small=62, or
Y+2X=62. We know y=x+2, so let's substitute x+2 for y
(x+2)+2x=62 simplify
x+2+2x=62 minus 2 both sides
3x=60 divide by 3
x=20
The smaller number is 20, so the larger is [20+2] 22.
The numbers are 20 and 22
Let's check:
They are consecutive even integers
and 22+2(20)=62 so there we go!
RELATED QUESTIONS
find two consecutive even integers such that the sum of the larger and twice the smaller... (answered by checkley71)

find two consecutive even integers such that the sum of the larger and twice the smaller... (answered by TheProdicalSon)

Find two consecutive even integers such that the sum of the larger and twice the smaller... (answered by neatmath)

Find two consecutive even integers such that the sum of the larger and twice the smaller... (answered by mananth)

Find two consecutive even integers such that the sum of the larger and twice the smaller... (answered by Lenzky)

find two consecutive even integers such that the smaller added to five times the larger... (answered by Alan3354)

Find two consecutive even integers such that the sum of the smaller integer plus twice... (answered by Alan3354)

Find two consecutive even integers such that the sum of the larger and three times the... (answered by College Student)

find two consecutive even integers such that the smaller added to twice the larger gives... (answered by MathLover1)