SOLUTION: Find two consecutive integers such that twice the smaller is 16 more than the larger

SOLUTION: Find two consecutive integers such that twice the smaller is 16 more than the larger

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Question 566026: Find two consecutive integers such that twice the smaller is 16 more than the larger
Answer by ad_alta(240) (Show Source): You can put this solution on YOUR website!
Let 'n' be the smaller integer. Then 2n=(n+1)+16. Solving, we get n=17. The integers are 17 and 18.
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