SOLUTION: find the smallest of three consecutive positive integers such that the product of two smaller integers is 68 more than twice the largest integer

SOLUTION: find the smallest of three consecutive positive integers such that the product of two smaller integers is 68 more than twice the largest integer

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Question 565645: find the smallest of three consecutive positive integers such that the product of two smaller integers is 68 more than twice the largest integer
Answer by ad_alta(240) (Show Source): You can put this solution on YOUR website!
Let 'n' be the smallest integer. Then n(n+1)=68+2(n+2). We get n=9. The positive integers are 9, 10, 11.
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