SOLUTION: find three consecutive integers such that the product of the first and the second is equal to the product of -6 and the third.

Question 556089: find three consecutive integers such that the product of the first and the second is equal to the product of -6 and the third.
Answer by TutorDelphia(193) (Show Source): You can put this solution on YOUR website!
Three consecutive integers. If we say the first one is n, than the 3 will be n, n+1 and n+2
Therefore we can write the problem as
n*(n+1)=-6*(n+2)
Distribute the n and -6

Add 6n to both sides

add 12 to both sides

factor
(n+3)(n+4)=0
n=-3 or -4
So our integers would be -3,-2,-1
or -4,-3,-2
-3*-2=-1*6
6=6
-4*-3=-2*-6
12=12

RELATED QUESTIONS
find three consecutive positive odd integers such that the product of the first and third (answered by CubeyThePenguin)

Find three consecutive positive odd integers such that the product of the first and third (answered by stanbon)

Find three consecutive positive odd integers such that the product of the first and third (answered by richwmiller)

Find three consecutive positive odd integers such that the product of the first and third (answered by amarjeeth123)

Find three positive consecutive integers such that the product of the first and second is (answered by Boreal,FrankM)

find three consecutive even integers such that the product of the first and second is... (answered by CubeyThePenguin)

Find three consecutive integers such that the product of the first integer and the second (answered by checkley71)

Find three consecutive odd integers such that the product of the second and third minus... (answered by josgarithmetic)

Find three consecutive integers such that the product of the first and the third is... (answered by ewatrrr)