SOLUTION: the sum of 4 consecutive integers of 114

SOLUTION: the sum of 4 consecutive integers of 114

Algebra.Com

Question 551826: the sum of 4 consecutive integers of 114
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
n + n+1 + n+2 + n+3 = 114

4n+6=114

4n=114-6

4n=108

n=(108)/(4)

n=27

So the first number is 27 and the four numbers are: 27, 28, 29, 30
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