SOLUTION: 8 times the largest of three consecutive odd integers is 1 more than the sum of 3 times the smallest integer and 8 times the middle integer. The middle integer is.

Question 54982: 8 times the largest of three consecutive odd integers is 1 more than the sum of 3 times the smallest integer and 8 times the middle integer. The middle integer is.
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
8 times the largest of three consecutive odd integers is 1 more than the sum of 3 times the smallest integer and 8 times the middle integer. The middle integer is.
:
First realize that when you count by odd numbers, you are adding 2. Observe,
1, 1+2,1+2+2,1+2+2+2...
1,3,5,7...
Therefore
Let the smallest number=x
Let the middle number=x+2
Let the largest number=x+2+2=x+4
8 times (8*)the largest (x+4)of three consecutive odd integers is(=) 1 more (+1) than the sum (+)of 3 times (3*)the smallest integer (x) and 8 times (8*)the middle integer (x+2). The middle integer is (x+2=).
8(x+4)=3x+8(x+2)+1
8x+32=3x+8x+16+1
8x+32=11x+17
-8x+8x+32=-8x+11x+17
32=3x+17
32-17=3x+17-17
15=3x
15/3=3x/3
5=x
The smallest integer:x=5
The middle integer:
The largest integer:x+4=5+4=9
Happy Calculating!!!

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