SOLUTION: Find two consecutive integers such that the product of the two integers is 12 more than the square of the smaller integer?

SOLUTION: Find two consecutive integers such that the product of the two integers is 12 more than the square of the smaller integer?

Algebra.Com

Question 544819: Find two consecutive integers such that the product of the two integers is 12 more than the square of the smaller integer?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the integers be x & x+1
x(x+1)=x^2-12
x^2+x=x^2-12
x=-12
The numbers are -12 & -13
RELATED QUESTIONS
Find three consecutive positive integers such that twice the product of the two smaller... (answered by JBarnum)

find two consecutive integers whose product is 7 more than the square of the smaller... (answered by Maths68)

Find three consecutive integers such that the square of the largest is 22 more than the... (answered by josgarithmetic,ikleyn)

The product of two consecutive odd integers is 10 more than the square of the smaller... (answered by stanbon,drj)

The product of two consecutive integers is 9 more than the square of the smaller one.... (answered by ewatrrr)

find the two consecutive integers such that the square of the smaller is 10 more than the (answered by josmiceli)

Find four consecutive integers such that the product of the two larger integers is 22... (answered by jorel1380)

find two consecutive positive integers such that the square of the smaller is one more... (answered by oberobic)

Find two consecutive Even integers such that the square of the smaller is 10 more than... (answered by mananth)