SOLUTION: The square of the first of three consecutive odd integers is 9 more than 6 times the sum of the second and third. Find the integers.

SOLUTION: The square of the first of three consecutive odd integers is 9 more than 6 times the sum of the second and third. Find the integers.

Algebra.Com

Question 534852: The square of the first of three consecutive odd integers is 9 more than 6 times the sum of the second and third. Find the integers.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the 3 consecutive odd integers be
, ,
given:

The numbers are 15, 17, and 19
check:

OK
RELATED QUESTIONS
find three consecutive positive odd integers such that the square of the first is 9 more... (answered by ankor@dixie-net.com)

The square of the first of three consecutive odd integers is 9 more than 6 times the sum... (answered by mananth)

Find three consecutive odd integers such that 6 times the sum of the first and second is... (answered by Boreal)

Three times the sum of the first and third of three consecutive odd integers is 55 more... (answered by stanbon,MathTherapy)

Consider three consecutive odd integers. The sum of the first integer and 2 times the... (answered by jorel555,josgarithmetic,MathTherapy)

Five times the second of three consecutive odd integers is thirteen less than three times (answered by josmiceli)

Five times the second of three consecutive odd integers is twelve less than three times... (answered by CubeyThePenguin)

Find three consecutive odd integers such that the sum of the first and second is 5 more... (answered by f_alsafi)

Find three consecutive odd integers, such that the sum of the second and third is... (answered by CubeyThePenguin)