SOLUTION: find an expression for the sum of five consecutive even integers

Question 531255: find an expression for the sum of five consecutive even integers
Found 2 solutions by algebrahouse.com, stanbon:
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
Even integers increase by two each time

x = 1st even integer
x + 2 = 2nd even integer
x + 4 = 3rd even integer
x + 6 = 4th even integer
x + 8 = 5th even integer

x + x + 2 + x + 4 + x + 6 + x + 8 {added all even integers}
= 5x + 20 {combined like terms}

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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find an expression for the sum of five consecutive even integers
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Even integers are always a multiple of 2.
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1st: 2x-4
2nd: 2x-2
3rd: 2x
4th: 2x+2
5th: 2x+4
----
Expression of sum:
2x-4+2x-2+2x+2x+2+2x+4
=============
Cheers,
Stan H.
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